Showing posts with label David Alg 2. Show all posts
Showing posts with label David Alg 2. Show all posts

Tuesday, December 7, 2010

3D Graph



For my 3D graphing project, my group chose the problem; (x+y+z=
3). My part was 7, which is x,y,-z. Then plug it into the equation x+y+z=3, and it'll be (3,3,-3).Then I graph it on a X,Y,Z graph and get the sided triangular plane.

Monday, December 6, 2010

Ch 3.4 Linear Programming

























For my chapter 4 project, I had to create my own linear programming problem and graph it. This was my problem: Andy is planing a green roof that will cover 750 square feet. He uses two types of plants; California Poppy and Oregon Sunshine. Each California Poppy covers 1 square fee ,and each Oregon Sunshine covers 1.5 square feet. California Poppy and Oregon Sunshine both cost $3 dollars each plant, and he must spend less than $2,000. First I made four different equations. C is less than or equal to 0 and O is less than of equal to 0. C standing for California poppy and 0 for Oregon Sunshine. Also 1c+1.5o is less than or equal to 750 and 3c+3o is less than or equal to 2,000. I have to make those two equations y intercept(y=mx+b). Then it becomes C is less than or equal to -1.5o+75, and C is less than or equal to 2000/3 which is around 666. Then I graph them each separate and one together for their feasible region. The vertices are (0,0), (666.666,0), (750,500), (0,500)

Friday, October 29, 2010

Ch 2 Project

















































For my Ch. 2 Project. I picked the car model Ferrari California. First I found out the mileage (miles per gallon) as the speed is at 55,60,65,70,75,and 80. Then I plotted the points on the graph. The graph was a negative correlation so it was going to have a negative slope. Then I drew the line of best fit. I found out the two points of the line of best fit and found the slope to be -5.3/25x. Then I used the point-slope form(y-y1=slope(x-x1) to write an equation. It turned out to be y=-5.3/25x+30.66. I plugged in all the plots to my graphing calculator to find out the correlation coefficient r(R=1 is postivite and R=-1 is a negative) and it was R=-.991. The R value tells that if you drive faster miles per gallon goes down, and that the graph is a negative correlation with almost a -1 coefficient, which is a straight negative line. I found that in the calculator the line of best fit(y=ax+b) was; a=-.2262857143, b=21.77428571. I plugged in if the speed of the car goes 55 miles per hour it would be -5.3/25(55)+30.66 which equals to 19 mpg and my prediction if the speed is 28 miles per hour it would be 40mph

Thursday, September 30, 2010

Ch 1 Real World Function Project






































By David Alg2
Equals(David Alg2 and Michael Negative)
This is our Real World Function Project for Ch 1. We learned in our class about functions and relations. We had to choose a real world one to graph for our project. Me and my partner, Michael decided to choose Tv Remote as our real world function. For our project the independent variable was the buttons in the remote. Our dependent variable was all the different channels. Our domain was all the buttons and range was the channels. Our function fails when you press 1 or any number and goes to any channel that is not suppose to go to. It happens if the Y value(channels) contain more than 1 when we use the vertical test. We prove that it is not a function most of the time, because they're are a lot of tv channels depending on the cable you have.

Thursday, September 16, 2010


























My name is David Rectangle. I went to Lincoln Elementary and Edna Brewer Middle school. During summers I sometimes volunteer at Occjcc.I helped kids in the program by teaching them and cooking for them. I also bring them to Lincoln Square Park and watch them play around. I haven't decided on my life goal yet. As I get near college I will decide. My hobbies are being on the computer, playing games, basketball, and hanging out with my friends.