Thursday, December 9, 2010
For this project, I built a model of a linear equation in three dimensions. The equation that my group and I chose was 3x+4y+2z=12. To graph it in 3D, there were 8 different ordered triples. The ordered triple that I had to do was (x, -y, -z). So the equation then became 3x-4y-2z=12. In order to graph it I had to find the x, y, and z intercepts. To find the intercepts, I plugged in zero to solve for one variable and repeat for the remaining variables. The intercepts I found were (4,0,0) , (0,-3,0) , & (0,0,-6). I plotted and connected my points and ended up with a 3D plane. The group and I then put together each section and it turned out like so.